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Jack Kilby demonstrated the first working integrated circuit in 1958 at which company?
Texas Instruments, on a tiny bar of germanium.
- Texas Instruments ✔
- Intel
- IBM
Why: On 12 September 1958, Kilby showed TI managers an oscillator circuit built on one small germanium bar. It earned him the 2000 Nobel Prize in Physics.
Huh, didn't know that: Robert Noyce at Fairchild separately developed a silicon IC soon after, which became the way chips are made.
Kilby put a whole circuit on one chip. Talk about integration skills.
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References
Answer: Texas Instruments. On 12 September 1958, Kilby showed TI managers an oscillator circuit built on one small germanium bar. It earned him the 2000 Nobel Prize in Physics.
- IEEE ETHW, Milestones: First Semiconductor Integrated Circuit (IC), 1958 ethw.org/Milestones:First_Semiconductor_Integrated_Circuit_%28IC%29%2C_1958
On 12 September 1958, Jack S. Kilby demonstrated the first working integrated circuit to managers at Texas Instruments.
Checked 2026-10-10.
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